WCS1800 Hall Current Sensor Detector 35A Current Sensor Module Board Short Circuit Overcurrent Protection Module Sensor with Overcurrent Lamp

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Choose JESSINIE for your development board and electronic components needs. Thank you for choosing JESSINIE. WCS1800 Hall current sensor has two main functions, the first function is an analogue signal followed by an op-amp, which is suitable for
A/D conversion: the second function is a switching signal, which can be pre-set to limit the value of the current, and when the actual current value is greater than the pre-set value of the current, the switching signal will be changed from a low level to a high level, and there is a LED indicator to show the value of the current. Simple and easy to use.
Operating voltage: DC5V
Current detection range:
DC: 35A, AC: 25A (for analogue output)
Linearity: K = 60mV / A.
Limit current range: 0.5A - 35A (for switching output) sampling current conversion analogue voltage signal output, can be connected to ADC, TTL level signal output, can be connected to the microcontroller I0 port control.
Output signal is: analogue voltage signal and switching signal indicator: with overcurrent indicator Power supply positive; VCC.
DOUT: TTL high/low level signal output; VCC.
GND: Negative terminal of power supply.
AOUT: Sampling current signal conversion voltage output terminal Method of application 1, analogue voltage signal output (AOUT) instructions for use: detection current and analogue signal output relationship is as follows: analogue
signal output: V0 = ± Ia * K (which la current Detection of the foot of the actual flow of current, K for the degree of linearity);. Input current 1A, for example, Vcc = 5V, WCS1800 linearity is 60mV / A We simply say that the wCS1800 detects the current and the output voltage corresponds to the relationship between the current flowing in from the positive direction. Formula V0=+la*K, corresponding
to the output: V0=( 2.5 + 0.06 )V= 2.56V When the current flows in the opposite direction. Formula V0 = -la*K, corresponding
to the output: V0 = ( 2.5 - 0.06 )V = 2.44V If it is an
AC signal: V0 = +la*K, V0 corresponding to the output range: 2.44V - 2.56V. The above is the ideal value, the actual value will have a certain small precision error. 2, switching output (DOUT) instructions for use if the current in a circuit, if the current is higher than 1A, the module is required to output a high level.
Step 1: put the detection end of a wire through the sensor hole (note that the current from the positive flow into), and then open the power supply, the detection end of the current to 1A state against the clock screw adjustable resistor Vref, has been controlled to the red LED bright moment that is good (LED from not bright to bright conversion point that is good, do not screw). At this time Vref>Vo.
Step 2: the above current limit 1A current settings have been completed. Remove the 1A current, the LED is bright, step
3: later when the current of the detected end exceeds 1A, the red LED does not light, this time the module DOUT output high level. See More